4^4x=8 find x
\[\large\rm 4^{4x}=8\]The x is in the denominator like this?
I suppose we could apply natural log to each side, then we'll be able to use a log rule to remove the x from the exponent position.
\[\large\rm \ln(4^{4x})=\ln8\]
Recall your log exponent rule,\[\large\rm \color{orangered}{\ln(a^b)=b\cdot \log(a)}\]
That allows us to bring the 4x out of the exponent position,\[\large\rm 4x\cdot \ln4=\ln8\]
From that point, solve for x, k? :) @lexiquesse
sorry, i was working on a different problem, but is it 1/2? @zepdrix
Nope
oops i meant 1 and 1/2
I don't understand. Are you just guessing? :o Do you understand how to solve for x?
.375? no im not, i took ln(8)/ln(4) and got 1.5, and 1.5/4=.375
4^4x = 8 Notice that both 4 and 8 are powers of 2 : (2^2)^4x = 2^3 2^8x = 2^3
im very confused
.375, yayy good job \c:/ Ahh I forgot we could simply do the exponent method for this one, doh!
its okay:p
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