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OpenStudy (princesssleelee):
What is the exact value of x in the exponential equation 2^8x − 3 = 7?
x = log4/8log2
x = 1/8log2
x= 5/8
x =log5/8
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OpenStudy (wolf1728):
Tke logarithms of both sides
OpenStudy (wolf1728):
Take
OpenStudy (princesssleelee):
Im not exactly sure on how to do that
OpenStudy (wolf1728):
2^8x − 3 = 7
Okay, I'll take logarithms of both sides
2^8x = 10
log (2^8*x) = log(10)
8x * log(2) = log(10)
8x * 0.30102999566 = 1
Can you solve from here?
OpenStudy (wolf1728):
Maybe it should stay as
8x * log(2) = 1
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OpenStudy (princesssleelee):
find x by solving:
8x * 0.30102999566=1?
OpenStudy (wolf1728):
OR
8x * log(2) = 1
OpenStudy (wolf1728):
Divide both sides by 8 * log(2)
OpenStudy (princesssleelee):
I solved that and got B :) is that correct?
OpenStudy (wolf1728):
Yes. See it's just that simple LOL
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OpenStudy (princesssleelee):
the decimal really threw me off! lol
OpenStudy (wolf1728):
okkay - you've got it
OpenStudy (princesssleelee):
Do you mind helping me with a few more? :)
OpenStudy (wolf1728):
I think I see another problem that I could help someone else
Maybe post the problem and I might get back
OpenStudy (princesssleelee):
Of course! Thank you! I will give you a medal each time!
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