What is the exact value of x in the exponential equation 2^8x − 3 = 7? x = log4/8log2 x = 1/8log2 x= 5/8 x =log5/8
Tke logarithms of both sides
Take
Im not exactly sure on how to do that
2^8x − 3 = 7 Okay, I'll take logarithms of both sides 2^8x = 10 log (2^8*x) = log(10) 8x * log(2) = log(10) 8x * 0.30102999566 = 1 Can you solve from here?
Maybe it should stay as 8x * log(2) = 1
find x by solving: 8x * 0.30102999566=1?
OR 8x * log(2) = 1
Divide both sides by 8 * log(2)
I solved that and got B :) is that correct?
Yes. See it's just that simple LOL
the decimal really threw me off! lol
okkay - you've got it
Do you mind helping me with a few more? :)
I think I see another problem that I could help someone else Maybe post the problem and I might get back
Of course! Thank you! I will give you a medal each time!
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