Question

Calculus Help anyone?

Answer 1

if you are determining if 1,2,3 are equivalent to the initial expression

then
first try expanding the series part in 1
and compare the expansion to the terms in the initial expression

please let me know what you think about 1 after doing this

Answer 2

Well, I know that 2 and 3 are both '2.' I forget how to do 1

Answer 3

@freckles

Answer 4

example on expanding the sum
\[\sum_{i=1}^{3} f(i)=f(1)+f(2)+f(3)\]

Answer 5

try expanding the sum in number 1 just a little

Answer 6

\[\sum_{k=1}^{n} \frac{\pi}{n} \sin(\frac{k \pi}{n})\]
this means you are going to add terms of the form pi/n sin(k*pi/n)
starting at the integer k=1 then k=2 and then so on to k=n

Answer 7

Ahhh I'm still a little confused

Answer 8

\[\sum_{\color{red}{k=1}}^{\color{blue}{n}} \frac{\pi}{n} \sin(\frac{\color{red}{k} \pi}{n})\]

Answer 9

Is there a definite answer for 1? Or are there multiple?? @freckles

Answer 10

(pi(sin)(pi/n)/(n) ??? @freckles

Answer 11

you do know that one symbol means to add right?

Answer 12

\[\sum_{\color{red}{k=1}}^{\color{blue}{n}} \frac{\pi}{n} \sin(\frac{\color{red}{k} \pi}{n}) \\ =\frac{\pi}{n} \sin(\frac{\color{red}1\pi}{n})+\frac{\pi}{n}\sin(\frac{\color{red}2 \pi}{n})+\frac{\pi}{n} \sin(\frac{\color{red}3 \pi}{n})+ \cdots +\frac{\pi}{n} \sin(\frac{ \color{blue}{n} \pi}{n})\]

Answer 13

there is one answer for 1

Answer 14

@dmezzullo

Answer 15

@zepdrix Hey since you're doing amazing could you help me on this one? :)