For the graphed function f(x) = (2)x + 2 + 1, calculate the average rate of change from x = −1 to x = 0.
\[f(x)=(2)^{x+2}+1\] this is how its written
this is how the grpah looks
Was an illustration included in the problem statement? Thanks for using Equation Editor. I was going to prompt you for an explanation of what you meant by your original function. Have you previously found the "average rate of change" for some other function in some other problem? If so, write out the formula for "average value of f(x) on interval [a, b]"
thats the illiystration ^^
Note that the interval of interest here is [-1,0]. illiystration ??
illustration*
illustration
so, what is the formula for "average rate of change of a function on the interval [a,b]"?
is it a(x)= f(x)-f(a)/x-a?
Sorry for the delay. Please, enclose "f(x)-f(a)" and "x-a" within square brackets, e. g., [f(x)-f(a)]. This is really important. Given\[f(x)=(2)^{x+2}+1\]
please evalute this at a=-1 and b=0. Your results?
Hold on my openstudy wont load so im on my phone app right now
\[f(-1)=(2)^{-1+2}+1,~and~f(0)=(2)^{0+2}+1.\]
Is it 3 and 5?
do i just subtract 3-5 to get the answer? i got -2
@mathmale
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