Question

What is the inverse of g(x) = x + 8 / 3 ?

G - 1 (x) = 3x + 8
G - 1 ( x) = x + 3 / 8
G - 1 ( x) = 3x - 8
G - 1 (x) = 3x + 3/-8

Answer 1

The given function is this right?
\[\Large g(x) = \frac{x+8}{3}\]

Answer 2

@jim_thompson5910 yes

Answer 3

So we follow these steps

step 1) Replace g(x) with y
step 2) Swap x and y
step 3) solve for y


\[\Large g(x) = \frac{x+8}{3}\]
\[\Large y = \frac{x+8}{3}\]
\[\Large x = \frac{y+8}{3}\]

are you able to solve for y?

Answer 4

Am I subtracting 3 since its positive ? @jim_thompson5910

Answer 5

the first step is to multiply both sides by 3

this is to undo the division of 3

Answer 6

\[\Large x = \frac{y+8}{3}\]
\[\Large 3x = y+8\]
what comes next?

Answer 7

You subtract y ? @jim_thompson5910

Answer 8

nope you subtract 8 from both sides

\[\Large 3x = y+8\]
\[\Large 3x-8 = y+8-8\]
\[\Large 3x-8 = y\]
\[\Large y = 3x-8\]

So the inverse function is
\[\Large g^{-1}(x) = 3x-8\]

Answer 9

Ok thank you @jim_thompson5910