Question

calculus help

Answer 1

R is the first quadrant region enclosed by the x-axis, the curve y=2x+a, and the line x=a, where a>0. Find the value of a so that the area of the region R is 18 square units.

A.3
B.3.772
C. 4.242
D. 9

Answer 2

The x-intercept of y=2x+a is x = -a/2

So, you have a triangle with base 3a/2 and height 3a, so the area is 9a^2/4.

If \[ 9a^2/4 = 18, a = √8 \]

check:

\[∫[-a/2,a] 2x+a dx = 9a^2/4\]

Answer 3

sqrt 8 isnt an answer choice @Ineedhelplz

Answer 4

...hmm

Answer 5

let's see if he can help

Answer 6

@mrm

Answer 7

Hi guys. Let me see what you have done so far.