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Mathematics 16 Online
OpenStudy (dontknowdontcare):

Anyone help me some?

OpenStudy (dontknowdontcare):

An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain to Maurice how to find the equation of the parabola given the focal point and the directrix.

OpenStudy (cas_fangirl_14):

draw a perpendicular line from the directrix passing through the focus, this will be the line of symmetry. The vertex(h, k) will be located on the line half way between the focus and directrix. The distance from the focus to the vertex is called the focal length, call it a. The then equation is (x - h)^2 = 4a(y - k) the equation can be manipulated to y = 1/4a(x - h)^2 + k hope it helps

OpenStudy (dontknowdontcare):

Is this answer correct? @Cas_fangirl_14

OpenStudy (dontknowdontcare):

First, you will draw a line of symmetry from the directrix, going through the focus. You then use the distance formula to simplify your focus points. Once they’re simplified you’ll get the distance between your focus and any given point on the parabola. That is equal to the equation (y2-y1)2. The directix is equal to y1, and once it is simplified, the equation comes out.

OpenStudy (cas_fangirl_14):

Looks good to me. :)

OpenStudy (dontknowdontcare):

Yay, thankyou!

OpenStudy (cas_fangirl_14):

\(\color{Purple}{No~Problem~~:)}\)

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