Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (helpppplz):

calculus help

OpenStudy (helpppplz):

find \[d/dx \int\limits_{2}^{x^3}\ln(x^2)dx\]

OpenStudy (helpppplz):

OpenStudy (helpppplz):

thats what i have so far but idk whts next

OpenStudy (helpppplz):

@mrm

OpenStudy (mrm):

Since you're taking the derivative of an integral, there is a shortcut here. A derivative will undo an integral, you just need to know what the limits of integration are an plug them into the expression inside the integral.

OpenStudy (mrm):

Remember to do the chain rule.

OpenStudy (helpppplz):

I forgot what the chain rule is.. I'll try to do a step

OpenStudy (helpppplz):

ln(x^3)^2

OpenStudy (mrm):

\[d/dx \int\limits_{2}^{x^3}\ln(x^2)dx = f(x)\] we want to find f(x) let \[G(x) = \int\limits_{2}^{x}\ln(x^2)dx\] then \[G(x^3) = \int\limits_{2}^{x^3}\ln(x^2)dx \] then we can say \[\frac{d}{dx} G(x^3) = f(x)\]

OpenStudy (helpppplz):

Then do i plug in 2 into the the equation?

OpenStudy (irishboy123):

as formulated, the answer is zero https://i.gyazo.com/bad010ce977ce9953dba65406af53d16.png

OpenStudy (helpppplz):

I put it into my calc and got 18.5 as the answer, but I haveto show my work

OpenStudy (mrm):

You will not get a number. You will get some function of x... f(x).

OpenStudy (mrm):

You see that one of your limits of integration is a function of x, \[x^3\]

OpenStudy (irishboy123):

thanks Prof!! we just need to switch the letters about, if i can be so bold as to make a recommendation

OpenStudy (mrm):

when you differential the integral, you get \[\frac{d}{dx}G(x^3) = ln(x^6)dx\]

OpenStudy (helpppplz):

right. so now we plug in 2?

OpenStudy (mrm):

then by the chain rule we have to take the derivative inside G... what is the derivative of \[x^3\]

OpenStudy (helpppplz):

3x^2

OpenStudy (mrm):

so our answer is \[f(x) = 3x^{2}\ln(x^6)\]

OpenStudy (helpppplz):

and that's the simplest form?

OpenStudy (mrm):

Yep.

OpenStudy (helpppplz):

Thanks for your help!

OpenStudy (mrm):

No problem.

OpenStudy (irishboy123):

that's just nonsense it's actually a meaningless integral \(\dfrac{d}{dx} \int ANYTHING ~ dx = ANYTHING\) [ftc] the limits don't matter, and they mean nothing. so the answer is \(\ln (x^2)\) i was wrong to be so flippant, it just looked silly, but this is wrong too.....IMHO!!!

OpenStudy (agent0smith):

Irish has a point. It should be something like \[\Large d/dx \int\limits\limits_{2}^{x^3}\ln(t^2)dt\]not the way it was originally posted.

OpenStudy (irishboy123):

yep! no-one cares though!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!