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Physics 20 Online
OpenStudy (dtan5457):

resistors and currents

OpenStudy (dtan5457):

#6

OpenStudy (shamim):

can u tell me equivalent resistance of ur given circuit

OpenStudy (shamim):

i think u know the formula to calculate the equivalent resistance of 2 parallel resistance

OpenStudy (shamim):

at last u hv to calculate the equivalent resistance of 2 series resistance

OpenStudy (shamim):

u know \[\frac{ 1 }{ R _{p} }=\frac{ 1 }{ R _{1} }+\frac{ 1 }{ R _{2} }\]

OpenStudy (shamim):

\[R _{p}=\]

OpenStudy (shamim):

equivalent resistance of resistance R1 and R2

OpenStudy (shamim):

another formula is \[R _{s}=R _{1}+R _{2}\]

OpenStudy (shamim):

\[R _{s}=\]

OpenStudy (shamim):

equivalent resistance of 2 series resistance

OpenStudy (shamim):

at last u hv to use ohms law \[V=IR\]

OpenStudy (shamim):

i can discuss this math more efficiently if u r online

OpenStudy (ybarrap):

One quick way is to use Millman's Theorem to find voltage then use this to find the required current: https://en.wikipedia.org/wiki/Millman%27s_theorem $$ v=\cfrac{\cfrac{28}{7.1}}{\cfrac{1}{7.1}+\cfrac{1}{1.7}+\cfrac{1}{5.1}}\\ \implies I_{7.1\Omega}=\cfrac{28-v}{7.1}\text{ Amperes} $$

OpenStudy (ybarrap):

Does this make sense?

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