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OpenStudy (dtan5457):
#6
OpenStudy (shamim):
can u tell me equivalent resistance of ur given circuit
OpenStudy (shamim):
i think u know the formula to calculate the equivalent resistance of 2 parallel resistance
OpenStudy (shamim):
at last u hv to calculate the equivalent resistance of 2 series resistance
OpenStudy (shamim):
u know
\[\frac{ 1 }{ R _{p} }=\frac{ 1 }{ R _{1} }+\frac{ 1 }{ R _{2} }\]
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OpenStudy (shamim):
\[R _{p}=\]
OpenStudy (shamim):
equivalent resistance of resistance R1 and R2
OpenStudy (shamim):
another formula is
\[R _{s}=R _{1}+R _{2}\]
OpenStudy (shamim):
\[R _{s}=\]
OpenStudy (shamim):
equivalent resistance of 2 series resistance
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OpenStudy (shamim):
at last u hv to use ohms law
\[V=IR\]
OpenStudy (shamim):
i can discuss this math more efficiently if u r online
OpenStudy (ybarrap):
One quick way is to use Millman's Theorem to find voltage then use this to find the required current:
https://en.wikipedia.org/wiki/Millman%27s_theorem
$$
v=\cfrac{\cfrac{28}{7.1}}{\cfrac{1}{7.1}+\cfrac{1}{1.7}+\cfrac{1}{5.1}}\\
\implies I_{7.1\Omega}=\cfrac{28-v}{7.1}\text{ Amperes}
$$