resistors and currents
#6
can u tell me equivalent resistance of ur given circuit
i think u know the formula to calculate the equivalent resistance of 2 parallel resistance
at last u hv to calculate the equivalent resistance of 2 series resistance
u know \[\frac{ 1 }{ R _{p} }=\frac{ 1 }{ R _{1} }+\frac{ 1 }{ R _{2} }\]
\[R _{p}=\]
equivalent resistance of resistance R1 and R2
another formula is \[R _{s}=R _{1}+R _{2}\]
\[R _{s}=\]
equivalent resistance of 2 series resistance
at last u hv to use ohms law \[V=IR\]
i can discuss this math more efficiently if u r online
One quick way is to use Millman's Theorem to find voltage then use this to find the required current: https://en.wikipedia.org/wiki/Millman%27s_theorem $$ v=\cfrac{\cfrac{28}{7.1}}{\cfrac{1}{7.1}+\cfrac{1}{1.7}+\cfrac{1}{5.1}}\\ \implies I_{7.1\Omega}=\cfrac{28-v}{7.1}\text{ Amperes} $$
Does this make sense?
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