Question

Check my answer? Attachments below

Answer 1

This is similar to the last problem, but different.

The first part is taking out a blue marble; which was 3/12 or 1/4

Next, they say to take a red marble without replacing the blue one, which means your total is 1 less than it was

Answer 2

Oh, I see. So, I am not correct?

Answer 3

Hello?

Answer 4

In the first problem, we multiplied: \[\frac{ 1 }{ 4 }*\frac{ 1 }{ 4}*\frac{ 1 }{ 4 }\]because each time, you put the marble back (That means we had 12 total marbles in the bag each time.)

For this problem, we start off with 3/12, or 1/4. We don't replace it though, so when we draw the red marble, they're are only 11 total. They're are 5 red marbles, making the chance of drawing a red 5/11

So now again, we multiply those two numbers:

\[\frac{ 1 }{ 4 }*\frac{ 5 }{ 11 }=\frac{ (1*5) }{ (4*11) }=\frac{ ? }{ ? } \]

Answer 5

Oh. So, A?

Answer 6

Yep

Answer 7

Thank you!