Question

Please help!!!

Answer 1

\[[\sin^2\theta-(\cos^2\theta)(\sin^2\theta)]^{-1}\]

Answer 2

Where theta equals 30 degrees

Answer 3

use

a^(-1) = 1/a

and the difference of two squares

a^2 -b^2 = (a+b)(a-b)

so but before all you factoriz out the sin^2 theta and will get

sin^2 theta(1-cos^2 theta)

but you know that 1=sin^2(theta) +cos^2(theta)

than you substitute there inside paranthese will get cos^2 theta with -cos^2 theta deleted and what will remained there ???

hope this will help you

Answer 4

but again hope you know that sin 30° = 1/2

so this will help you ending your exercise ?

Answer 5

OH okay thank you!!! No i did not know sin 30 = 1/2.