Question

At a basketball game, members of the Spirit Club use a t-shirt cannon to launch team t-shirts to spectators in the stands. The equation below describes the height, h, of the t-shirt, t seconds after it is shot from the cannon c feet above the ground, at an initial velocity of v.
h = -16t 2 + vt + c
Solve the equation for initial velocity, v.
The cannon launched a t-shirt from an initial height of 5 feet. After 3 seconds the shirt has reached a height of 131 feet. Use your equation from #1 to find the initial velocity of the t-shirt. Show your work.
What does the equation from #1 tell y

Answer 1

tell you about the value of the velocity, v, when t = 0? Explain.

Answer 2

is that it

Answer 3

here's what i think
h = -16t 2 + vt + c
where h= 131 and t= 3 and C=5
now solve for v
131= -16(3)^2 + v(3) + 5
131= -144 + 3v + 5
131 + 144 -5 = 3v
270=3v
90=v

Therefore it took a velocity of 90 and time of 3sec to reach 131 height.

Answer 4

that's the right one. :) sorry for being late

Answer 5

Thank you for the medal :)

Answer 6

post your last question before i go to sleep.

Answer 7

ok so is that the answer u think

Answer 8

tell you about the value of the velocity, v, when t = 0? Explain.

you can say when they time is zero then
h = -16t 2 + vt + c
131= -16(0)^2 + v(0) + 5
therefore
131= 0 + 0v + 5
so basically the velocity is zero when the time is zero

Answer 9

make sense?

Answer 10

yeah

Answer 11

I might be confused... because I usually am, but 90 is the velocity at 3 secs into the flight, so the initial velocity should be greater?

You need to differentiate the distance equation to find the velocity at t = 0