Question

matlab help

Answer 1

@mjdennis

Answer 2

%% Problem 9.5
%{
Use the primes function to create a list of all the primes below 100. Now
use a for loop to multiply adjacent values together. For example, the first
four prime numbers are 2 3 5 7. Your calculation would be 2*3 3*5 5*7 which
gives 6 15 35
%}

% defing variables
a = 100;
c9p5 = primes(100);


for k = 1:length(c9p5)
a = c9p5(k) *

end

Answer 3

OK, so if your list were only 3 items long ([2 3 5]), do you need to execute the loop 3 times?
k=1: 2*3
k=2 3*5
K=3 5*oops-i-am-out-of-items...

Somehow you need to do one fewer steps...

Answer 4

Well the question asks all the primes below 100

Answer 5

never mind I figured it out

Answer 6

Correct, and c9p5 = primes(100); gives you the primes below 100, I think.

But, to find the problem in your code, let's model the problem as the primes less than 6 and use primes(6), length(c9p5) is now 3, right?
BUT DO WE DO 3 MULTIPLICATIONS to solve? No, only 2. See my last reply.

So instead of using "length(c9p5)' how do you get a loop one iteration shorter.

Answer 7

Oops, too late...

Answer 8

here I will show you what I have

Answer 9

% defing variables

p = primes(100);
a = zeros(1, length(p) - 1);

for i = 1:length(p) - 1
a(i) = p(i) * p(i + 1);
end