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Mathematics 19 Online
OpenStudy (kikuo):

http://prntscr.com/b6x5p6 7 I got v=414.7 http://prntscr.com/b6x5ug 9 I got V=123 in terms of pi SA=81 in terms of pi http://prntscr.com/b6x62n 6 I got 48 http://prntscr.com/b6x6hf 4. I got LA=28 terms of pi and SA=36 in terms of pi Are these correct?

OpenStudy (kikuo):

@jim_thompson5910

OpenStudy (kikuo):

As for the two questions I need help with, here they are. http://prntscr.com/b6x6q5

OpenStudy (zzr0ck3r):

what is the volume of the first one without the roof?

OpenStudy (kikuo):

Wouldn't it be 14x35x8?

jimthompson5910 (jim_thompson5910):

The answer you got for #7 is incorrect

OpenStudy (zzr0ck3r):

correct, now what is the area of a triangle?

OpenStudy (kikuo):

@jim_thompson5910 That's the only one? If so, what did I do wrong? @zzr0ck3r Well, I know the base is 14, but I'm not too sure how to find the height.

OpenStudy (zzr0ck3r):

well how tall is the building and how tall is it when you remove the roof? What is the difference?

jimthompson5910 (jim_thompson5910):

I haven't checked the others yet. Please only post one question per thread. To avoid confusion and clutter

OpenStudy (kikuo):

Sorry haha. I figured it would be easier this way. No problem, though.

OpenStudy (zzr0ck3r):

@Kikuo do you see the height of the triangle must be 2?

OpenStudy (kikuo):

No, I don't.

OpenStudy (jtvatsim):

|dw:1463890849154:dw|

OpenStudy (jtvatsim):

It's hard to see from the diagram... but perhaps they mean the diagonal is 10 feet? Just an idea...

OpenStudy (kikuo):

Oh hi there! Hold on let me look.

OpenStudy (zzr0ck3r):

I thought it meant the height was 10

OpenStudy (jtvatsim):

Has your class covered the Pythagorean theorem? Like a^2 + b^2 = c^2? If you haven't then just ignore my idea. : )

OpenStudy (zzr0ck3r):

so the triangle height is 2 so we have (1/2)2*14+14*8*35

OpenStudy (kikuo):

Yes! That sounds like the easiest way. I assume I use that to find the height. : )

OpenStudy (kikuo):

Question, where did the 14x8x35 come from? I assume that's the full volume, yes?

OpenStudy (zzr0ck3r):

err (1/2)2*35*14+14*8*35

OpenStudy (kikuo):

I'm a bit confused about what you're doing. Though, I did get the answer as you did for the height.

OpenStudy (zzr0ck3r):

yeah maybe ignore me, I was reading the thing wrong I think

OpenStudy (kikuo):

Alright, so what do we do?

OpenStudy (kikuo):

@zzr0ck3r

OpenStudy (zzr0ck3r):

depends on what 10 is. I can't tell from the picture.

OpenStudy (kikuo):

Ten is the side of the base @zzr0ck3r

OpenStudy (sachintha):

6,7 and 9(V) are wrong.

OpenStudy (kikuo):

@Sachintha 4 is correct? What did I do wrong for the other ones?

OpenStudy (sachintha):

Yes 4 is correct. 9(V) should be 121.5 so it's 122. For the rest you seem to have the formula wrong.

OpenStudy (sachintha):

6. Volume of square pyramid = \(\large a^2\Large\frac{h}{3}\) 7. Volume of cone = \(\large\pi r^2\Large\frac{h}{3}\)

OpenStudy (sachintha):

For 8, find the area of the gable wall and multiply with the length of the house to get the volume of it. For 10, get r for the SA and substitute it for formula of volume. \(\large49\pi=4\pi r^2\) \(\large\quad\; r =\Large\frac{7}{2}\) \(\begin{array}{ccc}\therefore &Volume~of~sphere &=&\Large\frac{4}{3}\pi r^2\\&&=&\Large\frac{4}{3}\pi(\frac{7}{2})\end{array}\)

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