Mathematics
10 Online
OpenStudy (lorenbeech):
Mass Calculus post...
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OpenStudy (lorenbeech):
OpenStudy (lorenbeech):
OpenStudy (lorenbeech):
@PaxPolaris
OpenStudy (kky10997):
ok 1st calculate area of rectange then calculate \[\int\limits_{0}^{\pi/2}\cos x dx\]
OpenStudy (kky10997):
then then calculate area of ractangle - ∫0π/2cosxdx
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OpenStudy (kky10997):
and calculate %
OpenStudy (lorenbeech):
\[\int\limits\limits_{0}^{\pi/2}cosxdx=1 \]
OpenStudy (kky10997):
for 2nd question option b is correct
OpenStudy (kky10997):
and also calculate area od rectangle
OpenStudy (lorenbeech):
Wouldn't that just be pi/2? @kky10997
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OpenStudy (kky10997):
yeah it is pi/2
OpenStudy (kky10997):
now calculate shaded area which is = pi/2-1
OpenStudy (lorenbeech):
.57
OpenStudy (kky10997):
now calculate %
OpenStudy (kky10997):
which is= (shaded area/area of rectangel) *100
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OpenStudy (lorenbeech):
36.3% :)
OpenStudy (kky10997):
yeah
OpenStudy (lorenbeech):
Thank you :)
OpenStudy (kky10997):
any time :)
OpenStudy (lorenbeech):
Could you help out with more?
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OpenStudy (kky10997):
for second qun it is continous coz there is no break graph (a,c)
OpenStudy (kky10997):
yeah
OpenStudy (lorenbeech):
So the second one is no longer b?
OpenStudy (kky10997):
yeah 2nd one is easy
OpenStudy (lorenbeech):
So it'd be 'I only'?
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OpenStudy (kky10997):
so 3rd condition also correct
OpenStudy (kky10997):
slope of both like arent equal so 2nd condition is wrong so option b is correct
OpenStudy (lorenbeech):
Oh right right
OpenStudy (lorenbeech):