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Mathematics 10 Online
OpenStudy (lorenbeech):

Mass Calculus post...

OpenStudy (lorenbeech):

OpenStudy (lorenbeech):

OpenStudy (lorenbeech):

@PaxPolaris

OpenStudy (kky10997):

ok 1st calculate area of rectange then calculate \[\int\limits_{0}^{\pi/2}\cos x dx\]

OpenStudy (kky10997):

then then calculate area of ractangle - ∫0π/2cosxdx

OpenStudy (kky10997):

and calculate %

OpenStudy (lorenbeech):

\[\int\limits\limits_{0}^{\pi/2}cosxdx=1 \]

OpenStudy (kky10997):

for 2nd question option b is correct

OpenStudy (kky10997):

and also calculate area od rectangle

OpenStudy (lorenbeech):

Wouldn't that just be pi/2? @kky10997

OpenStudy (kky10997):

yeah it is pi/2

OpenStudy (kky10997):

now calculate shaded area which is = pi/2-1

OpenStudy (lorenbeech):

.57

OpenStudy (kky10997):

now calculate %

OpenStudy (kky10997):

which is= (shaded area/area of rectangel) *100

OpenStudy (lorenbeech):

36.3% :)

OpenStudy (kky10997):

yeah

OpenStudy (lorenbeech):

Thank you :)

OpenStudy (kky10997):

any time :)

OpenStudy (lorenbeech):

Could you help out with more?

OpenStudy (kky10997):

for second qun it is continous coz there is no break graph (a,c)

OpenStudy (kky10997):

yeah

OpenStudy (lorenbeech):

So the second one is no longer b?

OpenStudy (kky10997):

yeah 2nd one is easy

OpenStudy (lorenbeech):

So it'd be 'I only'?

OpenStudy (kky10997):

so 3rd condition also correct

OpenStudy (kky10997):

slope of both like arent equal so 2nd condition is wrong so option b is correct

OpenStudy (lorenbeech):

Oh right right

OpenStudy (lorenbeech):

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