Question

im trying to simplify
2sin2x−2sinx+2∗3√cosx−√3=0

can someone give me a hint as to where to start?

Answer 1

can you write equation again

Answer 2

m trying to simplify
2sin2x−2sinx+2∗√3cosx−√2=0

can someone give me a hint as to where to start?

Answer 3

yeah

Answer 4

1st apply sin2x=2sinxcosx

Answer 5

then divide both side by cosx

Answer 6

ok

Answer 7

so now you get

Answer 8

[2sinxcosx-2sinx+2*\sqrt{3}cosx-\sqrt{3}\] then divide by cos

[2sinx-2*(sinx/cosx)+2\sqrt{3}-(\sqrt{3}/\cos)\]

Answer 9

where did you go? I can't figure it out. Please help