Question

Which graph best resembles the graph of x = a(y - k)^2 if a>0 h<0 k>0 ? (drawing below)

Answer 1

\[\Large x=a \left( y-k \right)^2+h\]

you forgot to write h

Answer 2

Can you eliminate at least on of the options? @chaotic_butterflies

Answer 3

I'm back, apologies, and there is an h acutally

Answer 4

I think I can eliminate D

Answer 5

yes ...y is being squared and not x

Answer 6

if the formula was \[y=a(x-h)^2+k\] the graph would open up or down

Answer 7

But since it's x, it's going to lay down right or left

Answer 8

\[\Large x=a \left( y-k \right)^2+h\]
correct

Answer 9

the coordinates of the vertex are (h,k)

Answer 10

h is negative and k is positive ... so we can rule out one more option

Answer 11

I don't know how that correlates with left and right

Answer 12

h is the x - coordinate which is negative
k is the y - coordinate which is positive

Which Quadrant must the vertex (h,k) be in?

Answer 13

The upper left quadrant

Answer 14

So it's a or b

Answer 15

right

Answer 16

now, if a is positive, the graph opens to the right (or up)

if a is negative, it opens to the left (or down)