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OpenStudy (natasha18):
The following is a 3-step proof. Complete the proof.
Given:<1 =< 2
AP = BP
Prove: triangle APD is congruent to triangle BPC
OpenStudy (natasha18):
OpenStudy (natasha18):
Can you make the three step proof and tell me how you did it??
OpenStudy (natasha18):
I get the general idea, but I never know which reasons and statements to use :/
OpenStudy (natasha18):
@nincompoop @jabez177 @Preetha
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OpenStudy (natasha18):
@Nnesha @myininaya @zepdrix @freckles
OpenStudy (natasha18):
can someone please help me??
jimthompson5910 (jim_thompson5910):
see attached for a hint
OpenStudy (natasha18):
@jim_thompson5910 can you help me??
jimthompson5910 (jim_thompson5910):
let me know if that hint helps or not
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OpenStudy (natasha18):
@jim_thompson5910 okay i think i know would the proof be:
Statement Reason
<1=<2 Given
<APD=<BPC Vertical <'s are =
triangle APD congruent to triangle BPC ASA
OpenStudy (natasha18):
@jim_thompson5910 is that right??
jimthompson5910 (jim_thompson5910):
very good, you nailed it
jimthompson5910 (jim_thompson5910):
don't forget to put in AP = BP
jimthompson5910 (jim_thompson5910):
otherwise, it looks good
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