a rope is swinging in such a way that the length of the arc is decreasing geometrically. If the first arc is 27 feet long and the fourth arc is 8 feet long, what is the length of the second arc?
@jim_thompson5910
my equation i came up with this 27(2/4)^n-1 is that not right?
`length of the arc is decreasing geometrically` so if 27 is the first arc length then 27*r is the second arc length where r is some value in the interval 0 < r < 1 the third arc is 27*r*r = 27*r^2 the fourth arc is 27*r^2*r = 27*r^3, and we're given it's equal to 8, so 27r^3 = 8 making r = ???
is it .6666
or 2/3
so 27*r = 27*(2/3) = ???
12
no
oh i did it squared to find the second
18
yep the second arc is 18 ft
wait wouldn't it be 12 because it is squared for 2nd
Common ratio: r = 2/3 first arc = 27 ft .... given second arc = (first arc)*(r) second arc = (27)*(2/3) second arc = 18 ft third arc = (second arc)*(r) third arc = (18)*(2/3) third arc = 12 fourth arc = (third arc)*(r) fourth arc = (12)*(2/3) fourth arc = 8 ... also given and this confirms what we're given
oh i see but idk why 18 isn't one of my answer choices
there's a typo somewhere I'm assuming
oh maybe. but u seem correct
The only thing you can do is bring it up with the teacher
yeah i'll ask. thank you!
no problem
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