a rope is swinging in such a way that the length of the arc is decreasing geometrically. If the first arc is 27 feet long and the fourth arc is 8 feet long, what is the length of the second arc?
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OpenStudy (watermelon14):
@jim_thompson5910
OpenStudy (watermelon14):
my equation i came up with this 27(2/4)^n-1 is that not right?
jimthompson5910 (jim_thompson5910):
`length of the arc is decreasing geometrically`
so if 27 is the first arc length then 27*r is the second arc length where r is some value in the interval 0 < r < 1
the third arc is 27*r*r = 27*r^2
the fourth arc is 27*r^2*r = 27*r^3, and we're given it's equal to 8, so
27r^3 = 8
making r = ???
OpenStudy (watermelon14):
is it .6666
jimthompson5910 (jim_thompson5910):
or 2/3
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jimthompson5910 (jim_thompson5910):
so 27*r = 27*(2/3) = ???
OpenStudy (watermelon14):
12
jimthompson5910 (jim_thompson5910):
no
OpenStudy (watermelon14):
oh i did it squared to find the second
OpenStudy (watermelon14):
18
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jimthompson5910 (jim_thompson5910):
yep the second arc is 18 ft
OpenStudy (watermelon14):
wait wouldn't it be 12 because it is squared for 2nd
jimthompson5910 (jim_thompson5910):
Common ratio: r = 2/3
first arc = 27 ft .... given
second arc = (first arc)*(r)
second arc = (27)*(2/3)
second arc = 18 ft
third arc = (second arc)*(r)
third arc = (18)*(2/3)
third arc = 12
fourth arc = (third arc)*(r)
fourth arc = (12)*(2/3)
fourth arc = 8 ... also given and this confirms what we're given
OpenStudy (watermelon14):
oh i see but idk why 18 isn't one of my answer choices
jimthompson5910 (jim_thompson5910):
there's a typo somewhere I'm assuming
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OpenStudy (watermelon14):
oh maybe. but u seem correct
jimthompson5910 (jim_thompson5910):
The only thing you can do is bring it up with the teacher