Fan and medal! Thank you so much♥ The sample space for a roll of two number cubes is shown in the table. (1,1)|(1,2)|(1,3)|(1,4)|(1,5),(1,6) (2,1)|(2,2)|(2,3)|(2,4)|(2,5)|(2,6) (3,1)|(3,2)|(3,3)|(3,4)|(3,5)|(3,6) (4,1)|(4,2)|(4,3)|(4,4)|(4,5)|(4,6) (5,1)|(5,2)|(5,3)|(5,4)|(5,5)|(5,6) (6,1)|(6,2)|(6,3)|(6,5)|(6,5)|(6,6) The two numbers rolled can be added to get a sum. Find P(sum is less than 4) A. 1/12 B. 5/36 C. 2/9 D. 11/12
How many different outcomes are there in the sample space?
Is the correct answer B?
No. Once again, how many different outcomes are there?
can someone help me with my question pls i dont mean to interupt
12? There are 6 outcomes per line, and there are 6 lines. What is 6 * 6?
36
Correct. Now count how many outcomes have a sum of less than 4.
Remember, we need "less than 4", so you want sums of only 2 and 3.
Here are some of the smaller sums in red. How many are less than 4? (1,1) Sum \(\color{red}{2}\)|(1,2) Sum \(\color{red}{3}\)|(1,3) Sum \(\color{red}{4}\)|(1,4)|(1,5),(1,6) (2,1) Sum \(\color{red}{3}\)|(2,2)Sum \(\color{red}{4}\)|(2,3) Sum \(\color{red}{5}\)|(2,4)|(2,5)|(2,6) (3,1) Sum \(\color{red}{4}\)|(3,2) Sum \(\color{red}{5}\)|(3,3)|(3,4)|(3,5)|(3,6) (4,1) Sum 5|(4,2)|(4,3)|(4,4)|(4,5)|(4,6) (5,1)|(5,2)|(5,3)|(5,4)|(5,5)|(5,6) (6,1)|(6,2)|(6,3)|(6,5)|(6,5)|(6,6)
Is the correct answer A?
Right. There are 3 sums under 4: (1,1), (1, 2), (2, 1) 3/36 = 1/12 A is correct.
OMG thank you so much and thank you for your patience with me!
You're welcome.
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