HELP ME GIING MEDALS AWAY ??????????????????
Explain how you can use the distributive property to check the binomial factors when a trinomial has been factored. Include an example in your explanation.
nVM I got it
here's the following trinomial \[x^2 +8x+12\] factor the above using 2 groups. what are 2 number when multiplied equal 12 and when added equals 8 that would be 6 and 2 Therefore the new shape would be \[x^2 +2x +6x + 12\] Now factor by groups \[(x^2+2x) (6x+12)\] Common factor for the 1st binomial would be: x Common factor for the second binomial would be 6 Now divide each binomial on it's factor. therefore the answer would be \[(x+2) (x+6)\] Now for the above binomial you can use distributive property to check if you answer is correct or not. let's try it out |dw:1464012543625:dw| which means we are going to multiply each variable or number from the 1st binomial to the whole 2nd binomial and so \[(x+2)(x+6)\] \[x*x = x^2\] \[x*6 = 6x\] \[2*x= 2x\] \[2*6= 12\] Combine like terms \[x^2 + 6x + 2x +12\] which would equal \[x^2 +8x +12\] which is the same trinomial we factored. which means our answer is correct. hope that helps. :)
thxs
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