Use the given graph of f to find a number δ such that if |x − 1| < δ then |f(x) − 1| < 0.2
thats the graph. How to do this question?
you can interpret |f(x) − 1| < 0.2 to mean "the maximum distance of f(x) from 1 is less than 0.2" another way is to say |f(x) − 1| < 0.2 means 0.8 < f(x) < 1.2 the graph shows exactly this.
the graph also shows that |f(x) − 1| < 0.2 if 0.7 < x < 1.1 i.e. if 0.7 < x < 1.1 then we know |f(x) − 1| < 0.2 however, that interval is not symmetric. we want to find δ |x − 1| < δ or 1-δ < x < 1 + δ notice if we use the interval 0.9 < x < 1.1 we are still guaranteed that |f(x) − 1| < 0.2 and using 0.9 < x < 1.1, we have a symmetric interval with δ = 0.1 so one answer to the question (we could use a smaller interval, so in theory there are infinite number of answers): δ = 0.1
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