Probability help
An urn contains 2 white and 3 red balls. Four persons a,b,c and d in this order draw a ball without replacement. One who draws a white ball wins. Find their respective chances of winning.
Clearly P(A) = 2/5 and then I made a tree to determine the proceeding winners in this way : But the answer for P(B) comes out to be 4/5 which is wrong. Any ideas ?
Waapas JEE prep mein lag gaye kya? :|
dusra account kyu? :O
did you account for the non replacement? it doesn't look like you did on the tree
I've made changes to values of white and red balls after winning or losing written in brackets(W,R)
i'll draw a quick tree and see if I notice any discrepancies between them
You seem to be correct. :\
Sure. Thanks!
@L tell me something new? :) however the answer in my textbook is 3/10 for B and 2/5 for A(which is correct)
Wait, the tree you drew... the game pretty much ends at the white ball, doesn't it? So if A picks the white ball up, then you have to exclude that part of the tree!
I have 3/10 for B as well 2/4 * 3/5 = 6/20 = 3/10
In other words, the only way for B to pick a ball up is when A fails to. So you only look at the right side of the tree.
Oh..totally neglected that (: dunno why it didn't seem obvious to me :P
thanks @wilsondanielle :)
no problem! what do you have for c and D?
1/5 and 1/10
3/5*2/4*2/3 for C and 3/5*2/5*1/3*1/2 for D
Those are what I got to. It ends up being a pattern : A = 4/10 (2/5), B = 3/10, C = 2/10 (1/5), D = 1/10
too*
yep :D beautifully
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