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Mathematics 15 Online
OpenStudy (dontknowdontcare):

A carnival ride is in the shape of a wheel with a radius of 15 feet. The wheel has 24 cars attached to the center of the wheel. What is the central angle, arc length, and area of a sector between any two cars? Round answers to the nearest hundredth if applicable. You must show all work and calculations to receive credit.

OpenStudy (dontknowdontcare):

@jabez177 do you know thus?

OpenStudy (dontknowdontcare):

@mrm @Mehek14

OpenStudy (anthonyym):

The central angle would be 360 degrees divided by how many cars.

OpenStudy (dontknowdontcare):

Okay, so 15 is the central angle

OpenStudy (dontknowdontcare):

how do I find the arc length?

OpenStudy (anthonyym):

Arc length is S = theta*r, where the angle theta is in radians

OpenStudy (dontknowdontcare):

Could I find it with what information is given?

OpenStudy (anthonyym):

So the arc length using degrees would be S = (pi/180)*theta*r Because multiplying by pi/180 converts an angle in degrees to radians.

OpenStudy (dontknowdontcare):

And what is theta here?

OpenStudy (anthonyym):

theta is the central angle 15 degrees, and r is radius.

OpenStudy (dontknowdontcare):

Would it be 225?

OpenStudy (dontknowdontcare):

@anthonyym

OpenStudy (anthonyym):

No. You have \[\frac{ \pi }{ 180 }*15*15\]. And also the circumference is 94.25 feet, so an arc length of that can't be larger.

OpenStudy (dontknowdontcare):

I got 3.925?

OpenStudy (dontknowdontcare):

@anthonyym

OpenStudy (anthonyym):

Yes good. Now for the area between the two cars, it would be theta/360 * pi*r^2

OpenStudy (anthonyym):

theta is still the central angle

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