What are the center and radius of the circle with equation (x+2)^2+(y-9)^2=16
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OpenStudy (mathmale):
Compare your "(x+2)^2+(y-9)^2=16" to the standard equation of a circle with center at (h,k) and radius r:\[(x-h)^2+(y-k)^2=r^2\]
Can you read off the values of h, k and r through this comparison?
OpenStudy (mathmale):
Compare (y-9) to (y-k). This is the easiest comparison. What is the value of k?
OpenStudy (annalee607):
9
OpenStudy (mathmale):
Yes, and so the center of your circle is (h, 9).
What is the x-coordinate of the center? Do another comparison. Be very careful with your signs + and - .
OpenStudy (annalee607):
2
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OpenStudy (mathmale):
No. Try again. Compare (x-k) to (x+2). Are the signs the same?
OpenStudy (annalee607):
-2
OpenStudy (mathmale):
Look at the right side of your equation: 16. thios represents r^2. What is r?
OpenStudy (mathmale):
So, the coordinates of the center of your circle are ( ? , ? )
OpenStudy (annalee607):
(-2,9) Radius 4
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OpenStudy (mathmale):
Perfect. Review our discussion. Then you'll be done.