Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (study_buddy99):
\[\frac{ 5x^2y }{ 8}* \frac{2x ^{-1}y}{ x^3y }\]
OpenStudy (ivettef365):
i believe this case would be easier to multiply first and then simplify
OpenStudy (ivettef365):
multiplication of exponents is just adding
OpenStudy (ivettef365):
do the top part first
OpenStudy (study_buddy99):
okay so 3xy^2?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ivettef365):
you have 5x^2y . 2x^-1y
OpenStudy (ivettef365):
so 5 x 2 = 10 then x^(2-1) then y^(1-1)
OpenStudy (study_buddy99):
10xy
OpenStudy (ivettef365):
so you have
10xy^2
--------
8x^3y
OpenStudy (ivettef365):
sorry I meant y^(1+1) on the y
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ivettef365):
do you see how I got to that point?
OpenStudy (study_buddy99):
yes, I messed up the equation a little bit that 2 is supposed to be negative making it -10
OpenStudy (ivettef365):
oh ok then you have the following
-10xy^2
--------
8x^3y
OpenStudy (ivettef365):
are we good up to there
OpenStudy (study_buddy99):
yes
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ivettef365):
ok, now to divide exponents you have to subtract, but to make everything positive whatever is negative you bring down
only the digits you simplify as you always done so
-10/8 = -5/4 then you have x^(1-3) and y^(2-1)
OpenStudy (ivettef365):
so you have -5/4 x^-2 y^1
OpenStudy (ivettef365):
do you follow what I did ?
OpenStudy (study_buddy99):
yes
OpenStudy (ivettef365):
the way you right it now is
-5y
------
4x^2
Still Need Help?
Join the QuestionCove community and study together with friends!