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Mathematics 16 Online
OpenStudy (study_buddy99):

simplify the expression?

OpenStudy (study_buddy99):

\[\frac{ 5x^2y }{ 8}* \frac{2x ^{-1}y}{ x^3y }\]

OpenStudy (ivettef365):

i believe this case would be easier to multiply first and then simplify

OpenStudy (ivettef365):

multiplication of exponents is just adding

OpenStudy (ivettef365):

do the top part first

OpenStudy (study_buddy99):

okay so 3xy^2?

OpenStudy (ivettef365):

you have 5x^2y . 2x^-1y

OpenStudy (ivettef365):

so 5 x 2 = 10 then x^(2-1) then y^(1-1)

OpenStudy (study_buddy99):

10xy

OpenStudy (ivettef365):

so you have 10xy^2 -------- 8x^3y

OpenStudy (ivettef365):

sorry I meant y^(1+1) on the y

OpenStudy (ivettef365):

do you see how I got to that point?

OpenStudy (study_buddy99):

yes, I messed up the equation a little bit that 2 is supposed to be negative making it -10

OpenStudy (ivettef365):

oh ok then you have the following -10xy^2 -------- 8x^3y

OpenStudy (ivettef365):

are we good up to there

OpenStudy (study_buddy99):

yes

OpenStudy (ivettef365):

ok, now to divide exponents you have to subtract, but to make everything positive whatever is negative you bring down only the digits you simplify as you always done so -10/8 = -5/4 then you have x^(1-3) and y^(2-1)

OpenStudy (ivettef365):

so you have -5/4 x^-2 y^1

OpenStudy (ivettef365):

do you follow what I did ?

OpenStudy (study_buddy99):

yes

OpenStudy (ivettef365):

the way you right it now is -5y ------ 4x^2

OpenStudy (study_buddy99):

okay, I see. Thank you so much!

OpenStudy (ivettef365):

you're welcome :)

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