Question

Identify the vertex and the axis of symmetry of the graph of the function y=2(x+2)^2-4

Answer 1

What would we do first?

Answer 2

What is the formula for finding the Vertex

Answer 3

idk

Answer 4

\[a(x-k)^{2}+h\]
(k,h)

Answer 5

So in this case what is K and what is H ?

Answer 6

k=2, h=-4

Answer 7

Close, look at the formula

(x-k) becomes (k) So what happens to the K?

Answer 8

it becomes a positive

Answer 9

Correct so what is H and K?

Answer 10

h=-4, and k=-2?

Answer 11

Correct so what is the Vertex?

Answer 12

Hint: Vertex is always the X value

Answer 13

Seems like you stepped away for a minute :/

Don't worry i finish it off for you :D

Answer 14

The vertex will be -2
(-2,-4) V = -2

What i like to do is go to x= -2 on the graph and draw a dotted line Vertically On the line to show where it suppose to be.

Then we plot the points (-2,-4)

Now we need 2 more points to complete the graph. So we have -2 as the vertex so just pick 2 numbers lower so -1 and 0

2(-1+2)^2-4 = -2
2(0+2)^2-4 = 4
So we have

(-1,-2) & (0,4)

Now we have to reflect across the the vertex -2 and So we will have for point (-1,-2) it will be reflected to the other side of the Vertex which would be (-3,-2) & Same for (0,4) which would be (-3,4). So we would have something like this

Answer 15

sorry for the delay, Thanks

Answer 16

You're Welcome