Question

NEED HELP

Answer 1

@mathstudent55

Answer 2

@Vocaloid

Answer 3

@butterflydreamer

Answer 4

@F_Jayyy

Answer 5

@Vocaloid

Answer 6

@emogirl100 @smartnerd1111

Answer 7

@Qwertty123 @kky10997

Answer 8

there is only 1 function

Answer 9

there is only 1 function

Answer 10

SECOND FUNCTION: f(x)=3x^2+12x+16

Answer 11

@kky10997

Answer 12

the more detailed steps the better please If you can help

Answer 13

see range of sin is
[-1,1] so range of g(x)=[-2,2]

Answer 14

ok

Answer 15

now try to second function

Answer 16

Try to plot

Answer 17

f(x)=3x^2+12x+16
D={b^2-4ac} in this case D< 0 so f(x)>0 for all x
so g(x) is min

Answer 18

Could I please just have the steps of how to do it? I really just need to have a thing to study rather than do it right now

Answer 19

So thats all?

Answer 20

yeah

Answer 21

I got the g(x) is minimum, and so those are all of the steps of how to get this answer? Bc i need to explain it to someone else as well so just making sure

Answer 22

@kky10997

Answer 23

@jim_thompson5910 @Vocaloid

Answer 24

@iwanttogotostanford focus on y = 3x^2+12x+16

notice how it's in the form y = ax^2+bx+c

Answer 25

do you agree that

a = 3
b = 12
c = 16

?

Answer 26

@jim_thompson5910 yes

Answer 27

@phi

Answer 28

I can't tell which question you are working on.

Answer 29

wait what is the question???

Answer 30

the one that is posted; i only posted one question.

Answer 31

can you repost it

Answer 32

this: Using complete sentences, explain how to find the minimum value for each function and determine which function has the smallest minimum y-value.

Answer 33

2x - sin (2x - pi) + 4*
x= -2 and 3pi/4

Answer 34

and then what? Could yu please expound on your answer and reasoning a bit? so i can understand better @supersmart1001

Answer 35

ok hold on

Answer 36

ok!

Answer 37

You can find the minimum value of each function by first finding the critical points and then using the second derivative test. The second derivative test tells you that if f "(x) < 0 at the critical point, then you have a maximum and if f "(x) > 0 at the critical point then you have a minimum. The critical points can be found by finding the derivative of the function and setting the function equal to 0.

f '(x) = 6x + 12 =0 => x = -2

g '(x) = 4cos(4x - π) = 0 => 4x - π = π/2, 3π/2, etc.

x = 3π/8, 5π/8, 7π/8, etc.

Note that since f "(x) = 6 > 0, we have a minimum at x = -2

g "(x) = -16sin(4x - π) > 0 for x = 5π/8, etc.

So therefore, g(5π/8) = 2sin(π/4) + 4 = 4 + √2 > f(-2) = 4

I hope this helps

Answer 38

thank you! so that is all to this question?

Answer 39

yes

Answer 40

also, could i please have help with another if i tag you ?

Answer 41

sure i wont beable to answer right away but yes i will help u

Answer 42

ok thanks!

Answer 43

np :3