Can someone help me understand this and answer it? What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over 3?
Which is: X+6 X-3 _____ ------ X+4 + 3
This is like adding (1/3) + (1/4), you have to convert the fractions before adding them together:
Do you mean multiplying the denominators so they're the same?
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My network is dropping my posts. Yes, so take each fraction. 1/3, for instance. Multiply top and bottom by the other denominator. (1/3) * (4/4) = 4 /12 The other term in my example becomes 3/12, and now you can add 4/12 + 3/12
The first term is easy, right? X+6 (3) _____ ___ X+4 (3)
What do you get for the second term? Remember to multiply top and bottom by the bottom of the other term.
Sorry my internet is being a pain too. So the first term would be 3x+18 ------ 3x+12 and then I believe the 2nd term would be x-3 (x+4)= x^2+x-12 ---------- 3x+12 If thats correct.
is it right to have a trinomial as the numerator?
3x+18 x^2+x-12 ------ + ---------- 3x+12 3x+12 and then I would just combine the top 2 right? How would I combine that tho
Yes it is!
now add the tops
btw, I would leave the bottom as 3(x+4) it's easier to see if anything will "cancel" if you do that
well, you combine the fractions just like adding (4/12) +(3/12) = (4+3)/12 = 7/12 Or, are you having trouble adding the two top expressions? To do this, we 'group like terms together', a math code for group any terms that have x^2 together, then x terms, then numbers. So if you had 4x+16 + 3x^2+2x-1 you have 3x^2 +4x+2x +16-1 And they add to 3x^2 +6x +15
I think I got it, it would be x^2 +4x+6 ---------- 3(X+4) Thank you so much!! I just totally forgot how to do it lol. Will medal and fan.
Last step: factor the top, if you can.
Oh, and pretend I used the correct math terms, "numerator" and "denominator", instead of "top" and "bottom"
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