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OpenStudy (memyselfandpi):
Pick a two-digit number greater than 25. Rewrite your two-digit number as a difference of two numbers. Show how to use the identity (x − y)^2 = x^2 − 2xy + y^2 to square your number without using a calculator.
10 years ago
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OpenStudy (memyselfandpi):
Please help.
10 years ago
likeabossssssss (likeabossssssss):
\(\Huge\color{#EB00FF}{\text{WELCOME}}\) \(\Huge\color{blue}{\text{TO}}\) \(\Huge\color{green}{\text{OPEN}}\)\(\Huge\color{purple }{\text{ STUDY!!!!!!!!!!!}}\) \(\Huge\heartsuit\)
10 years ago
OpenStudy (memyselfandpi):
Thank You :)
10 years ago
OpenStudy (memyselfandpi):
@Mehek14
10 years ago
OpenStudy (michele_laino):
I can choose 30=35-5
10 years ago
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OpenStudy (memyselfandpi):
Ok, how can I work this problem out though? That's what I am having trouble with.
10 years ago
OpenStudy (michele_laino):
next, I can write this:
\[900 = {30^2} = {\left( {35 - 5} \right)^2} = {35^2} + {5^2} - 2 \times 35 \times 5=...\]
10 years ago
OpenStudy (memyselfandpi):
900 + 25 - 2 x 35 x 5 = 575, if I am supposed to evaluate
10 years ago
OpenStudy (michele_laino):
we have this step:
\[\begin{gathered}
{30^2} = {\left( {35 - 5} \right)^2} = {35^2} + {5^2} - 2 \times 35 \times 5 = \hfill \\
\hfill \\
= 1225 + 25 - 350 = ...? \hfill \\
\end{gathered} \]
10 years ago
OpenStudy (memyselfandpi):
1225 + 25 -350 = 900.. Which is 30^2
10 years ago
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OpenStudy (michele_laino):
that's right!
10 years ago
OpenStudy (memyselfandpi):
Thank you. :)
10 years ago
OpenStudy (michele_laino):
:)
10 years ago
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