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Chemistry 8 Online
OpenStudy (marcoreus11):

I need help can someone help me I don't understand how to do them

OpenStudy (marcoreus11):

OpenStudy (marcoreus11):

@Photon336

OpenStudy (marcoreus11):

i know u need to use the boiling and freezing pint for these problems but none of them look the same

OpenStudy (marcoreus11):

@i don't know how to plug them in

OpenStudy (marcoreus11):

@sweetburger help plz

OpenStudy (marcoreus11):

@Photon336 hey photon i have to go to sleep but whenever u get on could u do 1 or 2 problems any so when i wake up i can see how u did it? thx

OpenStudy (frostbite):

@MarcoReus11 it is simply to plug into an equation for you. Let me write it along with it's units: \[\Large \Delta T_f=K_f \times b \times i\] Here is: \(\Delta T_f\): The change in freezing temperature of the solvent. unit: \([K]\) \(K_f\): The freezing-constant of the solvent. unit:\(\large [\frac{K ~ kg}{mol}]\) \(b\): The molality of the solute. unit: \(\large [\frac{mol}{kg}]\) \(i\) The Van't Hoff factor of the solute (how much ions the solute form in dissolved). unit: none If questions please write and we take a look at it together.

OpenStudy (frostbite):

solute form when dissolved*

OpenStudy (marcoreus11):

Are u still here?

OpenStudy (marcoreus11):

It says change in temperature don't I need to subs tract from either 100 or 0 right if they give me the temperature in freezing

OpenStudy (marcoreus11):

Or do I just plug in the temperature they give me

OpenStudy (frostbite):

No they want you to calculate how much NaCl you would need to lower the freezing temperature by 2 C of 150 gram of water. So all you gotta do is to solve for the morality of the solute, to find how many molal NaCl you need. Then from that you can calculate how many gram of NaCl you would need.

OpenStudy (marcoreus11):

Okay I solved I take a pic and show u

OpenStudy (marcoreus11):

Here

OpenStudy (marcoreus11):

@Frostbite help me!!!!!

OpenStudy (frostbite):

The issue for me is I can't see any units on the paper you are given.

OpenStudy (marcoreus11):

I converted g to kg

OpenStudy (marcoreus11):

-4.96 to -4960

OpenStudy (marcoreus11):

I mean kg to g

OpenStudy (marcoreus11):

Could u please do like 1 0r 2 problems like 3 and 4 and like me follow them so I can do the others

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