I'm so confused Transform this to rectangular form rcsc(θ)=5
rewrite as \[\frac{r}{\sin(\theta)}=5\] as a first step
then \[r=5\sin(\theta)\] now replace \(\sin(\theta)\) by \(\frac{y}{r}\)
if i lost you yet, let me know only two more steps
This is my first time trying these so they are quite confusing to me hehe. But I am pretty sure I am following. You are replacing sin(theta) with y/r because of the equation y=rsin(theta) right?
rigth
so now we are at \[r=\frac{y}{r}\]right ?
oh no wrong \[r=\frac{5y}{r}\] forgot the 5
Okay, yes, I see :)
Here's how I did it. See the attached image. Either way, you'll get the same answer.
yeah same thing next would be \[r^2=5y\] and \[x^2+y^2=5y\]
Thank you so much both of you!! Can you help me with one more @satellite73
sure why not (if i can)
Haha! \[r=(4/2\cos \theta-3\sin \theta)\]
btw it might have been easier to replace \(\sin(\theta)\) byu \(\frac{y}{r}\)right away to get \[\frac{r^2}{y}=5\]in one step so you have lots of choices
\[r=\frac{4}{2\cos(\theta)-3\sin(\theta)}\]
Yes, that's it
i think it is a line in any case put \(\cos(\theta)=\frac{x}{r}\) and \(\sin(\theta)=\frac{y}{r}\) and do a bunch of agebra
\[r=\frac{4}{\frac{2x}{r}-\frac{3y}{r}}\]
That makes sense!
i would actually flip that sucker to make it less painful \[\frac{1}{r}=\frac{\frac{2x}{r}-\frac{3y}{r}}{4}\]
now multiply both sides by \(r\) you ca see they will go bye bye
Oh! Wow, that's amazing haha! And then just multiply by 4?
yeah i guess
you get something like \[4=2x-3y\] right?
That's what I got :)
Thank you so so much!
yw
Join our real-time social learning platform and learn together with your friends!