Question

THREE QUESTIONS HELP PLEASE THREE Q"s:

Answer 1

3.) An electric field has a positive test charge of 5.00 E-5 C placed in it. The force on the test charge is 0.600 N. The magnitude of the electric field at the location of the test charge is

3.00 E5 N/C
3.00 E4 N/C
1.02 E4 N/C
120. E4 N/C
1.20 E4 N/C

Answer 2

@supersmart1001

Answer 3

@Qwertty123 @Vocaloid

Answer 4

ans of 1st is binding energy

Answer 5

ans of 2nd=option a

Answer 6

r u guessing

Answer 7

@kky10997 R U GUESSING

Answer 8

no i am not

Answer 9

how did u get those then

Answer 10

in 1st proten's has negative charge so they repule is eachother so we need binding force to bind in a nucles and for that we need binding energy and that come from decreament from mass

Answer 11

e=mc^2 we also know that
so E_b = (n_Nm_N + n_Zm_Z - M)c^2,

Answer 12

for 2nd let assume 1st we have n resistors and R1= eq resistance so 1/R1=1/r1+1/r2+....+1/rn
now we increase no. resistors and we have N resistors N>n and now re resistance=R2
1/R2=1/r1+1/r2+.......+1/rn+1/rn+1+......+1/rN
1/R2=1/R1+1/rn+1+....+1/rN
so 1/R2>1/R1
SO R2<R1

Answer 13

@supersmart1001 now u understand

Answer 14

idk what to do im totally lost too

Answer 15

yeah

Answer 16

@xapproachesinfinity @

Answer 17

@welshfella @831CHEYENNE831

Answer 18

srry chare on proton is +ve not -ve so sorry for that