Question

A line passes through (-3, -2) and is perpendicular to 3x - 2y = 7.

What is the equation of the line in slope-intercept form?

a) y=3/2x
B) y=3/2x+4
c) y=2/3x-4
d) y=-2/3x

Answer 1

first find the slope of the line 3x - 2y = 7
can you do that?

Answer 2

yea

Answer 3

ok so can you show me please?

Answer 4

its 3 rite

Answer 5

no wait ok 3x-2y=7 thats going to Be y=mx+b so the slope is m

Answer 6

so its gone be y=3/2x-7/2

Answer 7

its A

Answer 8

3/2 is the slope of the given line but the line they require is perpendicular to the given line so what is the slope of the line they require?

Answer 9

do you know this relationship ? -

if m = slope of a line then slope of a perpendicular line is -1 /m

Answer 10

i do now

Answer 11

yea lol

Answer 12

so the slope of required line = -1 / (3/2) = -2/3

Answer 13

so you can now write it , in slope intercept form, as

y = (-2/3) x + b

but you know it passes through the point x = -3 and y = -2 so plug these into this equation and solve for b.

knowing b you can write the required equation.

Answer 14

so it is A

Answer 15

How can it be A if the slope is -2/3???

Answer 16

The equations with a slope of -2/3 are c and d.

Answer 17

solve the equation for b and you'll get the answer
Can you do that?

Answer 18

x = -3 and y = -2 for the required equation so

-2 = (-2/3)* -3 + b

what is b?

Answer 19

ooooooooooo B=5/3

Answer 20

No (-2/3)* -3 = 6/3 = 2

so -2 = 2 + b

so b = ?

Answer 21

subtract 2 from both sides

Answer 22

4