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Mathematics
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OpenStudy (yessenia27):
Solve x3 = 64 over 27.
9 years ago
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OpenStudy (jakesaurus1127):
Is that supposed to say \[x^{3}\]
9 years ago
OpenStudy (haleyelizabeth2017):
\[x^3=\frac{64}{27}\]?
9 years ago
OpenStudy (yessenia27):
Yes
9 years ago
OpenStudy (xxstudyingstuffxx):
4 over 3
9 years ago
OpenStudy (haleyelizabeth2017):
Please do not give direct answers.
9 years ago
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OpenStudy (sunnnystrong):
Just take the cube root of 64/27
The answer is 4/3
9 years ago
OpenStudy (xxstudyingstuffxx):
Sorry
9 years ago
OpenStudy (haleyelizabeth2017):
Don't be sorry (:
9 years ago
OpenStudy (xxstudyingstuffxx):
\[\frac{ 4 }{ 3 }\]
9 years ago
OpenStudy (yessenia27):
But I want direct answers😂
9 years ago
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OpenStudy (yessenia27):
Solve x2 = −169.
9 years ago
OpenStudy (xxstudyingstuffxx):
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9 years ago
OpenStudy (yessenia27):
Solve x2 = −169.
9 years ago
OpenStudy (jakesaurus1127):
\[x^{3}=\frac{ 64 }{ 27 } \rightarrow \sqrt[3]{x^{3}}=\sqrt[3]{\frac{ 64 }{ 27 }} \rightarrow x=\frac{ \sqrt[3]{64} }{ \sqrt[3]{27} } \rightarrow x=\frac{ 4 }{ 3 }\]
9 years ago
OpenStudy (xxstudyingstuffxx):
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9 years ago
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OpenStudy (plainntall):
You can use a calculator for direct answers. That isn't fun though.
\[x ^{2}=-169\] is tricky because you can't multiply anything by itself and get a negative number. Mathematicians like to play pretend though so they made up and imaginary number and called it i
\[i==-1\]
That makes your problem
\[x=(\sqrt{169})i\]
9 years ago
OpenStudy (yessenia27):
What's the answer
9 years ago
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