Which of the graphs below correctly solves fo
@jhonyy9 @zepdrix
Look for the graph that shows y=-x-4 (straight line sloping down) and y=-x^2-3x-1 (parabola concave downwards).
There are sufficient hints to find the answer for this particular problem! Please re-read previous posts! :)
−x^2 − 3x − 1 = -x -4 so from these result what quadratic equation ?
will result x^2 +2x -3 =0 what can factorize it (x+3)(x-1) =0 do you can solve it now ?
do i factor?
x^2-1+3x-3 ? @jhonyy9
this is the text of your exercise Which of the graphs below correctly solves for x in the equation −x^2 − 3x − 1 = −x − 4?
will result x^2 +2x -3 =0 what can factorize it (x+3)(x-1) =0 do you can solve it now ?
just make x+3=0 and solve it for x and x-1=0 and solve it for x so how will get the x_1 and x_2 equales ?
so X= 1 and x=-3 @jhonyy9
@jim_thompson5910
@campbell_st
well here is a quick method... the line y = -x -4 where does it cut the y-axis...? the slope is negative and what you you know about the concavity of \[y = -x^2\] using those 3 pieces of infomration you can get the solution without having to do any major calculations.
@Nnesha
@wolf1728 @tori1423
Take the equation that you are given and separate it into two equations: \[y=-x^{2}-3x-1\]\[y=-x-4\] Then look at the graphs and see which one has both of those graphed.
@stacey thank you, finally someone who made some sense!
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