There is no way I can find the intercept form of
y=-2x^2-4x+3
... What am I supposed to do?

Question

There is no way I can find the intercept form of 
y=-2x^2-4x+3
... What am I supposed to do?

satellite73 · Answer

what does "intercept form" mean for a quadratic?

satellite73 · Answer

does it mean "factored form"?

mathmate · Answer

Intercept form :
y=a(x-x1)(x-x2)

jh99 · Answer

I'm sure they're asking for the factored form: y=a(x+r1)(x+r2)

jh99 · Answer

sorry minus*

mathmate · Answer

ref: http://www.ck12.org/book/CK-12-Algebra-II-with-Trigonometry-Concepts/section/5.16/

mathmate · Answer

So @satellite73 's suggested "factored form" is the same.

satellite73 · Answer

does not factor using integers

jh99 · Answer

so it's basically impossible?

satellite73 · Answer

using integers, yes

mathmate · Answer

@jh99
as @satellite73 said, it is impossible to express the given equation
y=$-2x^2-4x+3$
in intercept form using rational number.

However, either you find a typo in the question, or you'd have to accept the irrational version of the intercept form, which is not impossible:

You can factorize by using the quadratic formula, which gives
$x=\{-(\sqrt{10}+2)/2, (\sqrt{10}-2)/2\}$
which gives
$y=-\frac{1}{2}(2x+\sqrt{10}+2)(2x-\sqrt{10}+2)$