OpenStudy (supercalifragalisticexspeaalli):

Derive the equation of the parabola with a focus at (2, −1) and a directrix of y = −one half. f(x) = −(x + 2)2 − three fourths f(x) = (x + 2)2 + three fourths f(x) = −(x − 2)2 + three fourths f(x) = −(x − 2)2 − three fourths

1 year ago
OpenStudy (supercalifragalisticexspeaalli):

i need to solve it @XhawaiiangirlX

1 year ago
OpenStudy (xhawaiiangirlx):

Okay would you like steps or just a straight answer?

1 year ago
OpenStudy (supercalifragalisticexspeaalli):

well for now straight answer because i have 2 more but on the last one u can do steps

1 year ago
hero (hero):

Straight Answers are never acceptable on OS @XhawaiiangirlX

1 year ago
hero (hero):

@supercalifragalisticexspeaalli I guess you gave up on Slader.

1 year ago
OpenStudy (xhawaiiangirlx):

@Hero Please do not bring trouble thank you for the notification but if u look alot of other people they give straight answer. Also, i was just about to explain how i got the answer.

1 year ago
OpenStudy (supercalifragalisticexspeaalli):

how can u check it @XhawaiiangirlX yea lol it won't load on my laptop @Hero

1 year ago
OpenStudy (xhawaiiangirlx):

okay as i was saying we are trying to find the vertex

1 year ago
OpenStudy (xhawaiiangirlx):

To be specific the vertex form of a parabola

1 year ago
OpenStudy (supercalifragalisticexspeaalli):

yea

1 year ago
OpenStudy (xhawaiiangirlx):

The equation for this is y = a(x - h)^2 + k

1 year ago
OpenStudy (supercalifragalisticexspeaalli):

k

1 year ago
OpenStudy (xhawaiiangirlx):

(h, k) is the vertex but in this case it is (2,-1)

1 year ago
OpenStudy (supercalifragalisticexspeaalli):

k

1 year ago
hero (hero):

(2,-1) is the focus, not the vertex @XhawaiiangirlX

1 year ago
OpenStudy (xhawaiiangirlx):

(2,-1) is the vertex and focus inn this equation hero thx for pointing that out :)

1 year ago
OpenStudy (supercalifragalisticexspeaalli):

lol

1 year ago
hero (hero):

@XhawaiiangirlX that is not correct.

1 year ago
OpenStudy (xhawaiiangirlx):

I answer the rest in chat @Hero

1 year ago
hero (hero):

@supercalifragalisticexspeaalli are you familiar with the distance formula that applies to this kind of problem?

1 year ago
OpenStudy (supercalifragalisticexspeaalli):

kinda

1 year ago
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