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Mathematics 10 Online
zarkam21 (zarkam21):

Help please will medal

OpenStudy (bigbosssaint21):

go for it

zarkam21 (zarkam21):

OpenStudy (mjdennis):

Almost the same way we solved that other one. The angle <ABC is one-half of the sum of the two arcs.

OpenStudy (aveline):

Simply add 130 and 40 then divide by 2.

zarkam21 (zarkam21):

So 170 /2

zarkam21 (zarkam21):

85?

OpenStudy (aveline):

Right

OpenStudy (mjdennis):

Yes. Do you need more help understanding that formula? You seemed to get it last time, and this problem is simpler...

zarkam21 (zarkam21):

zarkam21 (zarkam21):

well is this 90?

OpenStudy (mjdennis):

The answer isn't 90 deg., but you will use 90 deg. to help solve.

zarkam21 (zarkam21):

180?

OpenStudy (mjdennis):

90 = (1/2) (arcAC + arcAD) 180 = arcAC + arcAD 180 = arcAC + 42 Keep solving for arcAC

zarkam21 (zarkam21):

138

OpenStudy (mjdennis):

There you go. Do you understand the steps? What do you find hardest about these problems?

zarkam21 (zarkam21):

Well do I just get the sides and equal them to 180?

zarkam21 (zarkam21):

zarkam21 (zarkam21):

This is 180?

OpenStudy (mjdennis):

Kind of the opposite. You get the two _arcs_ (what you call 'sides'). You and them up and divide by two, and you get the angle in the middle.

zarkam21 (zarkam21):

So for this one would I do 90+90

OpenStudy (mjdennis):

|dw:1464288772128:dw| So, maybe. The middle angel is 90, and you double it. What do think 90+90 is equal to?

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