Question

Which graph shows the quadratic function y = 3x2 − 12x + 10?

link to graphs: http://broward.flvs.net/webdav/assessment_images/educator_algebraI_v20/10_20_q36.jpg

Answer 1

well the choices can't been viewed...

so an easy solution might be to find the line of symmetry and then vertex of the parabola

the line of symmetry is

Answer 2

The following graph is labeled A: A four quadrant graph with a parabola opening up, passing through the points negative 3, 1, negative 2, negative 2, and negative 1, 1 with the vertex at 2, negative 2. The following graph is labeled B: A four quadrant graph with a parabola opening up, passing through the points 1, 4, 2, 1, and 3, 4 with the vertex at 2, 1. The following graph is labeled C: A four quadrant graph with a parabola opening up, passing through the points negative 3, 5, negative 2, 2, and negative 1, 5 with the vertex at negative 2, 2. The following graph is labeled D: A four quadrant graph with a parabola opening up, passing through the points 1, 1, 2, negative 2, and 3, 1 with the vertex at 2, negative 2.

Answer 3

There are four graphs

Answer 4

the symmetry axis of the parabola, has the subsequent equation:
\[\begin{gathered}
x = \frac{{ - b}}{{2a}} = \frac{{ - \left( { - 12} \right)}}{{2 \cdot 3}} \hfill \\
\hfill \\
x = 2 \hfill \\
\end{gathered} \]

Answer 5

the y-coordinate of the vertex, is:
\[y = 3 \cdot {2^2} - 12 \cdot 2 + 10 = ...?\]

Answer 6

\[y=3(x^2+4x+4-4)+10=3(x^2+4x+4)-12+10\]
\[y=3\left( x-2 \right)^2-2\]
\[\left( x-2 \right)^2=\frac{ 1 }{ 3 }\left( y+2 \right)\]
it is an upward parabola with vertex at (2,-2)

Answer 7

So which would be the correct graph of the equation?

Answer 8

i can help but i can't look at the link you attached

Answer 9

how exactly can i attach a file to this?

Answer 10

heres the graph of the quadrilateral listed
y= 3x^2 -12x + 10

Answer 11

you can see your options for vertex.

Answer 12

hope that helps:)

Answer 13

Thanks