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Mathematics 21 Online
OpenStudy (asdfghjkl):

can someone help me i half figured out this problem but got stuck.

OpenStudy (mathstudent55):

Did you use a calculator?

OpenStudy (xapproachesinfinity):

For PR you can use Pythagorean Theorem

OpenStudy (mathstudent55):

What number did you actually get, with all the decimal places?

OpenStudy (xapproachesinfinity):

should be 15.2315

OpenStudy (mathstudent55):

How did you get exactly 15.2?

OpenStudy (xapproachesinfinity):

before rounding that is

OpenStudy (mathstudent55):

Are you using a calculator? Is your calculator set to only 1 decimal place?

OpenStudy (mathstudent55):

You constructed a right triangle with legs 14 and 6 units long, then you measured the hypotenuse with a ruler?

OpenStudy (mathstudent55):

Ok. If you needed an answer correct to only the nearest tenth, you'd be correct, but to get the hundredth place, you need to use a different method.

OpenStudy (mathstudent55):

@xapproachesinfinity mentioned above that you can use the Pythagorean theorem. Do you know how to use it?

OpenStudy (mathstudent55):

\(a^2 + b^2 = c^2\) |dw:1464301072304:dw|

OpenStudy (mathstudent55):

I think that is what you were trying to write.

OpenStudy (mathstudent55):

The two sides called a and b are the legs of the right triangle. They are the sides that form the right angle. The side called c is the hypotenuse. It is opposite the right angle, and it is the longest side of a right triangle. Your two sides with lengths 14 and 6 are the legs that form the right angle. Use the Pythagorean theorem formula above, and replace a with 14 and b with 6. What do you get?

OpenStudy (mathstudent55):

No. You started correctly, but you don't multiply. Let's do this in a way that you don't loose track of what you're doing. We have a formula for this problem, so let's start by writing it. Our formula for this problem is the equation of the Pythagorean theorem. \(a^2 + b^2 = c^2\) Now we replace the values we know. \(a = 14\), and \(b = 6\) \(14^2 + 6^2 = c^2\) Now we square 14 and 6. Notice there is an addition sign between them, not a multiplication sign. \(196 + 36 = c^2\) Now add 196 and 36. What do you get?

OpenStudy (mathstudent55):

Yes. Now you have \(232 = c^2\) Switch sides: \(c^2 = 232\) If the square of c is 232, then 232 is the square root of c. Use a calculator to find the square root of 232. Then round off to the nearest hundredth.

OpenStudy (mathstudent55):

Now you see lots of decimal places. Now round off to the nearest hundredth.

OpenStudy (mathstudent55):

No. This is how you do it.

OpenStudy (mathstudent55):

|dw:1464303521852:dw|

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