can someone help me i half figured out this problem but got stuck.
Did you use a calculator?
For PR you can use Pythagorean Theorem
What number did you actually get, with all the decimal places?
should be 15.2315
How did you get exactly 15.2?
before rounding that is
Are you using a calculator? Is your calculator set to only 1 decimal place?
You constructed a right triangle with legs 14 and 6 units long, then you measured the hypotenuse with a ruler?
Ok. If you needed an answer correct to only the nearest tenth, you'd be correct, but to get the hundredth place, you need to use a different method.
@xapproachesinfinity mentioned above that you can use the Pythagorean theorem. Do you know how to use it?
\(a^2 + b^2 = c^2\) |dw:1464301072304:dw|
I think that is what you were trying to write.
The two sides called a and b are the legs of the right triangle. They are the sides that form the right angle. The side called c is the hypotenuse. It is opposite the right angle, and it is the longest side of a right triangle. Your two sides with lengths 14 and 6 are the legs that form the right angle. Use the Pythagorean theorem formula above, and replace a with 14 and b with 6. What do you get?
No. You started correctly, but you don't multiply. Let's do this in a way that you don't loose track of what you're doing. We have a formula for this problem, so let's start by writing it. Our formula for this problem is the equation of the Pythagorean theorem. \(a^2 + b^2 = c^2\) Now we replace the values we know. \(a = 14\), and \(b = 6\) \(14^2 + 6^2 = c^2\) Now we square 14 and 6. Notice there is an addition sign between them, not a multiplication sign. \(196 + 36 = c^2\) Now add 196 and 36. What do you get?
Yes. Now you have \(232 = c^2\) Switch sides: \(c^2 = 232\) If the square of c is 232, then 232 is the square root of c. Use a calculator to find the square root of 232. Then round off to the nearest hundredth.
Now you see lots of decimal places. Now round off to the nearest hundredth.
No. This is how you do it.
|dw:1464303521852:dw|
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