How do you solve 30(1.2)^x=45+3x.
Use the Lambert W function.
what is that
hey there:)
have you started anything or completely stuck
haven't started
dont know what to do first
hmm what do you know that can simplify this?
I was thinking first hand to make little clean \(30(1.2)^x-3x=45 \Longrightarrow 10(1.2)^x-x=15\)
though it does not seem to break to something easier to solve this we need some other analytical methods
IDK if you learned something of this sort though
algebra alone won't do
I'm smart I can probably understand it
in what course are you given this lol?
algebra 1
You'll need real analysis for this problem it's post calculus usually.
this is a bad question then
are you sure there was an x in the exponent and one that is not?
yes
calculus wont do this either
this is not for alg1 for sure
This foe is beyond you
run
I have a masters in math and I have never studied the things needed to solve stuff like this. There is a thing called "analytic continuation of the product log function"
\(\color{blue}{\text{Originally Posted by}}\) @daniel.ohearn1 Use the Lambert W function. \(\color{blue}{\text{End of Quote}}\) I was wondering that this function is about
what*
unless of course this is a special case and there is some trivial solution we are not seeing. But in general....this is not undergraduate math (I don't think).
nevermind
@zzr0ck3r I'm under gad math so this cannot be solved with complex?
I am not sure how this is solved.
i think i have the wrong information
oh ok!
could be a trivial solution like you said?
well in general \(a^x=x^b\) is not an easy thing to solve, but some are easy \(2^x=x^2\) has an easy solution 2.
that is what I meant by trivial, but not in this case.
Now I wish I took complex analysis.
yeah seems so, thanks for the clarification :) I just checked the graph they are two real solutions
isn't it a requirement for a math degree?
there is a solution for every integer
it is not at my school. You just need to take two years of graduate math. I did abstract algebra, topology, graph theory, and a little convex analysis.
No this is not a difficult problem.... Now that I think about it, although it can be solved I imagine with methods of real analysis. For algebra class I would try setting (1.2)^x= (x+15)/10 using your knowledge of graphs and the way they are shaped. At the point of there intersection you will have the solution for x.
There are two intersections amongst the reals.
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