Okay, there is like 5 things to figure out in this one. @jim_thompson5910
Here's the assignment.
ok let me read it over
Alrighty :)
ok I think I know what to do, but I need to do a bit of research to confirm. One second.
I can wait :) You are great help.
ok have you learned about compound interest? or have you seen this formula before? \[\Large A = P*\left(1+\frac{r}{n}\right)^{n*t}\]
Never seen this formula..
like i said this is on study island and there wernt lessons for it.
hmm strange how they ask you questions when they don't have lessons for it
anyways P = amount deposited r = interest rate n = compounding frequency t = time in years
how much money is put into the account?
$500
so P = 500
the interest rate is r = 1.8% = 0.018
n = 12 because we are compounding monthly (12 times a year)
t will depend on what month it is eg: if we're at month 0, then t = 0/12 = 0 if we're at month 1, then t = 1/12 = 0.83333.... etc etc
Okay
Let's calculate month 1
P = 500 r = 0.018 n = 12 For month 1, the time in years is t = 1/12 = 0.0833333333333333 Let's plug those values in to get this: \[\Large A = P*\left(1+\frac{r}{n}\right)^{n*t}\] \[\Large A = 500*\left(1+\frac{0.018}{12}\right)^{12*0.0833333333333333}\] \[\Large A = 500*\left(1+0.0015\right)^{12*0.0833333333333333}\] \[\Large A = 500*\left(1.0015\right)^{1}\] \[\Large A = 500*1.0015\] \[\Large A = 500.75\]
Use a calculator for much of these steps. If you don't have one, then use this http://web2.0calc.com/
@jim_thompson5910 i think it may be simpler than this. It's interest rate each month. So each month it increases by 1.8%, making it a much easier problem. Just multiply the last month by 1.018.
But there is more than 1 thing to figure out first i have to figure out the amount in the account over 4 months. so @jim_thompson5910 how do we do that?
oh my bad @agent0smith is right. The annual rate isn't 1.8%. That's the monthly rate
Read my reply above^^
so based on what @agent0smith said, we just multiply the last month amount (500) by 1.018 to get the next month Current month balance = (Previous month balance)*(1.018) Current month balance = (500)*(1.018) Current month balance = 509
month 0 = $500 month 1 = $509 to get month 2, multiply the previous month's balance (month 1) by 1.018 to get what?
518.162
month 2 balance = (month 1 balance)*(1.018) month 2 balance = (509)*(1.018) month 2 balance = 518.162 month 2 balance = 518.16 ... round DOWN to the nearest penny
month 3 balance = (month 2 balance)*(1.018) month 3 balance = (518.16)*(1.018) month 3 balance = 527.48688 month 3 balance = 527.48... round DOWN to the nearest penny
?
where are you stuck? @sarah.ranee
So 527.48688 rounded to the nearest penny is 527.48?
keep in mind it says that `banks always round down to the nearest cent`
so even if you had 527.48999999999999999999999999999 it would round down to 527.48 the bank would NOT round to 527.49
the bank is trying to save as much money as possible. Even if it's a single cent
Okay. SO now month 4 is 536.97464 rounded Down to 536.97?
Is that right?
month 4 balance = (month 3 balance)*(1.018) month 4 balance = (527.48)*(1.018) month 4 balance = 536.97464 month 4 balance = 536.97 ... rounding down to the nearest cent
yes you are correct
Yeah! :) SO now we have to find out that, If she had graphed the function what the Y intercept would be. Im totally not good with the whole y intercept thing.
the y intercept occurs when the x value (aka the input) is 0 the input in this case is the number of months at month 0, the y value is 500 so basically this is the starting amount
`If she had graphed the function ` then her graph would cross through 500 on the y axis |dw:1464327454141:dw|
Okay.
the graph would slope upward and be some sort of curve to indicate that her money is growing over time |dw:1464327499871:dw|
the steeper the curve, the faster the growth
So does this mean the Y intercept would be 500?
yes
months goes on the x axis |dw:1464327621185:dw|
account balance goes on y axis |dw:1464327639801:dw|
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