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Mathematics 13 Online
OpenStudy (sarah.ranee):

Okay, there is like 5 things to figure out in this one. @jim_thompson5910

OpenStudy (sarah.ranee):

Here's the assignment.

jimthompson5910 (jim_thompson5910):

ok let me read it over

OpenStudy (sarah.ranee):

Alrighty :)

jimthompson5910 (jim_thompson5910):

ok I think I know what to do, but I need to do a bit of research to confirm. One second.

OpenStudy (sarah.ranee):

I can wait :) You are great help.

jimthompson5910 (jim_thompson5910):

ok have you learned about compound interest? or have you seen this formula before? \[\Large A = P*\left(1+\frac{r}{n}\right)^{n*t}\]

OpenStudy (sarah.ranee):

Never seen this formula..

OpenStudy (sarah.ranee):

like i said this is on study island and there wernt lessons for it.

jimthompson5910 (jim_thompson5910):

hmm strange how they ask you questions when they don't have lessons for it

jimthompson5910 (jim_thompson5910):

anyways P = amount deposited r = interest rate n = compounding frequency t = time in years

jimthompson5910 (jim_thompson5910):

how much money is put into the account?

OpenStudy (sarah.ranee):

$500

jimthompson5910 (jim_thompson5910):

so P = 500

jimthompson5910 (jim_thompson5910):

the interest rate is r = 1.8% = 0.018

jimthompson5910 (jim_thompson5910):

n = 12 because we are compounding monthly (12 times a year)

jimthompson5910 (jim_thompson5910):

t will depend on what month it is eg: if we're at month 0, then t = 0/12 = 0 if we're at month 1, then t = 1/12 = 0.83333.... etc etc

OpenStudy (sarah.ranee):

Okay

jimthompson5910 (jim_thompson5910):

Let's calculate month 1

jimthompson5910 (jim_thompson5910):

P = 500 r = 0.018 n = 12 For month 1, the time in years is t = 1/12 = 0.0833333333333333 Let's plug those values in to get this: \[\Large A = P*\left(1+\frac{r}{n}\right)^{n*t}\] \[\Large A = 500*\left(1+\frac{0.018}{12}\right)^{12*0.0833333333333333}\] \[\Large A = 500*\left(1+0.0015\right)^{12*0.0833333333333333}\] \[\Large A = 500*\left(1.0015\right)^{1}\] \[\Large A = 500*1.0015\] \[\Large A = 500.75\]

jimthompson5910 (jim_thompson5910):

Use a calculator for much of these steps. If you don't have one, then use this http://web2.0calc.com/

OpenStudy (agent0smith):

@jim_thompson5910 i think it may be simpler than this. It's interest rate each month. So each month it increases by 1.8%, making it a much easier problem. Just multiply the last month by 1.018.

OpenStudy (sarah.ranee):

But there is more than 1 thing to figure out first i have to figure out the amount in the account over 4 months. so @jim_thompson5910 how do we do that?

jimthompson5910 (jim_thompson5910):

oh my bad @agent0smith is right. The annual rate isn't 1.8%. That's the monthly rate

OpenStudy (sarah.ranee):

Read my reply above^^

jimthompson5910 (jim_thompson5910):

so based on what @agent0smith said, we just multiply the last month amount (500) by 1.018 to get the next month Current month balance = (Previous month balance)*(1.018) Current month balance = (500)*(1.018) Current month balance = 509

jimthompson5910 (jim_thompson5910):

month 0 = $500 month 1 = $509 to get month 2, multiply the previous month's balance (month 1) by 1.018 to get what?

OpenStudy (sarah.ranee):

518.162

jimthompson5910 (jim_thompson5910):

month 2 balance = (month 1 balance)*(1.018) month 2 balance = (509)*(1.018) month 2 balance = 518.162 month 2 balance = 518.16 ... round DOWN to the nearest penny

jimthompson5910 (jim_thompson5910):

month 3 balance = (month 2 balance)*(1.018) month 3 balance = (518.16)*(1.018) month 3 balance = 527.48688 month 3 balance = 527.48... round DOWN to the nearest penny

OpenStudy (sarah.ranee):

?

jimthompson5910 (jim_thompson5910):

where are you stuck? @sarah.ranee

OpenStudy (sarah.ranee):

So 527.48688 rounded to the nearest penny is 527.48?

jimthompson5910 (jim_thompson5910):

keep in mind it says that `banks always round down to the nearest cent`

jimthompson5910 (jim_thompson5910):

so even if you had 527.48999999999999999999999999999 it would round down to 527.48 the bank would NOT round to 527.49

jimthompson5910 (jim_thompson5910):

the bank is trying to save as much money as possible. Even if it's a single cent

OpenStudy (sarah.ranee):

Okay. SO now month 4 is 536.97464 rounded Down to 536.97?

OpenStudy (sarah.ranee):

Is that right?

jimthompson5910 (jim_thompson5910):

month 4 balance = (month 3 balance)*(1.018) month 4 balance = (527.48)*(1.018) month 4 balance = 536.97464 month 4 balance = 536.97 ... rounding down to the nearest cent

jimthompson5910 (jim_thompson5910):

yes you are correct

OpenStudy (sarah.ranee):

Yeah! :) SO now we have to find out that, If she had graphed the function what the Y intercept would be. Im totally not good with the whole y intercept thing.

jimthompson5910 (jim_thompson5910):

the y intercept occurs when the x value (aka the input) is 0 the input in this case is the number of months at month 0, the y value is 500 so basically this is the starting amount

jimthompson5910 (jim_thompson5910):

`If she had graphed the function ` then her graph would cross through 500 on the y axis |dw:1464327454141:dw|

OpenStudy (sarah.ranee):

Okay.

jimthompson5910 (jim_thompson5910):

the graph would slope upward and be some sort of curve to indicate that her money is growing over time |dw:1464327499871:dw|

jimthompson5910 (jim_thompson5910):

the steeper the curve, the faster the growth

OpenStudy (sarah.ranee):

So does this mean the Y intercept would be 500?

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

months goes on the x axis |dw:1464327621185:dw|

jimthompson5910 (jim_thompson5910):

account balance goes on y axis |dw:1464327639801:dw|

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