Question

Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credit.

x2 + 4x + y2 − 6y = −4

Answer 1

@fuzzpuppy2 @Asad786

Answer 2

@zzr0ck3r

Answer 3

@ganeshie8

Answer 4

Start by grouping x terms and y terms separately

Answer 5

\(x^2 + 4x + y^2 − 6y = −4\)

\((x^2 + 4x) + (y^2 − 6y) = −4\)

Answer 6

Do you know how to complete the square ?

Answer 7

._. I'm lost

Answer 8

When I see numbers, I completely zone out mostly @ equations

Answer 9

and them not being multiple choice hurts my soul

Answer 10

general ewq. of the circle is,
\[x ^{2} + y ^{2} + 2gx + 2fy + c = 0\]
centre = ( -g , -f)
compare the above eq. with ur ques. and u will get the coordinates of the centre

Answer 11

can't avoid them, you should get used to it

Answer 12

x (x+4)+(y-6) y=-4

Answer 13

WAIT I THINK I GET IT

Answer 14

(x^2+4x+4)-4+(y^2-6y+9)-9=-4
(x+2)^2+(y-3)^2=9
(x+2)^2+(y-3)^2=3^2

Answer 15

?

Answer 16

the center of the circle is at (-2,3) and the radius is 3.

Answer 17

Am I right? @ganeshie8

Answer 18

@Hyuna301

Answer 19

yup.. ur are right

Answer 20

Thank you