Find the perimeter of a quadrilateral with vertices at C (−1, 2), D (−2, −1), E (2, −2), and F (1, 1). Round your answer to the nearest hundredth when necessary.
10.92 units 12.68 units 13.43 units 18.27 units
please help, been up all night doing hw
The perimeter is just the sum of the lengths of the sides. Meaning that you have to find the distance of: -CD -DE -EF -FC Use the distance formula: \[dist(p_1 , p_2 )=\sqrt{(x_2-x_1)^2 + (y_2-y_2)^2}\]
CD=10 DE=17 EF=10 FC=5
@Owlcoffee
good, now add them together. meaning that the perimeter of this quadrilateral will be the sum of the lengths of its sides
I got 42
What else do I do?
Nvm I got it
Thank for your help and for future people you square root those numbers and add them together giving you choice B
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