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Mathematics 15 Online
OpenStudy (dreamsawakes):

Find the perimeter of a quadrilateral with vertices at C (−1, 2), D (−2, −1), E (2, −2), and F (1, 1). Round your answer to the nearest hundredth when necessary.

OpenStudy (dreamsawakes):

10.92 units 12.68 units 13.43 units 18.27 units

OpenStudy (dreamsawakes):

please help, been up all night doing hw

OpenStudy (owlcoffee):

The perimeter is just the sum of the lengths of the sides. Meaning that you have to find the distance of: -CD -DE -EF -FC Use the distance formula: \[dist(p_1 , p_2 )=\sqrt{(x_2-x_1)^2 + (y_2-y_2)^2}\]

OpenStudy (dreamsawakes):

CD=10 DE=17 EF=10 FC=5

OpenStudy (dreamsawakes):

@Owlcoffee

OpenStudy (owlcoffee):

good, now add them together. meaning that the perimeter of this quadrilateral will be the sum of the lengths of its sides

OpenStudy (dreamsawakes):

I got 42

OpenStudy (dreamsawakes):

What else do I do?

OpenStudy (dreamsawakes):

Nvm I got it

OpenStudy (dreamsawakes):

Thank for your help and for future people you square root those numbers and add them together giving you choice B

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