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Robert weighs 144 pounds one month before he plans to run a marathon. If he loses 3 percent of his weight while training, what is his weight on the day of the marathon?
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Any ideas?
Recall: $$\Huge x\text{%}=\dfrac{a}{b}$$
144- 4.32 139.68 pounds
If he loses 3% of his weight, then he must weigh 100% — 3% = 97% of 144 pounds, right?
3% of Robert's weight = (0.03)(144 lbs) = 4.3 lbs If Robert loses 3% of his weight while training, on the day of the marathon he will weigh 144 - 4.3 = 139.7 lbs which is approximately 140 lbs this is the best i got . I hope I'm right ...
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97% of 144 $$\dfrac{97}{100}•144$$
Yes, you are right :-) Check it with 0.97•144
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