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Mathematics 18 Online
OpenStudy (mightychondrion):

Question is below.

OpenStudy (mightychondrion):

OpenStudy (mightychondrion):

If it wasn't clear, I need help with part C.

ganeshie8 (ganeshie8):

A min/max value for a function occurs when its derivative equals 0

ganeshie8 (ganeshie8):

here, In part a, you have an expression for the length of ladder function

ganeshie8 (ganeshie8):

In part b, you have its derivative

ganeshie8 (ganeshie8):

simply set the derivative equal to 0 and find the value of \(\theta\)

OpenStudy (mightychondrion):

So using the derivative function equal to 0, I'd find the value of theta that could either yield the max or min value of the ladder's length?

ganeshie8 (ganeshie8):

Exactly

OpenStudy (mightychondrion):

I attempt to proceed as follows but find that no solution can be calculated. Did I make another mistake? Thank you for helping by the way.

ganeshie8 (ganeshie8):

\(\sin^3 \theta = \cos^3\theta\) can we conclude \(\sin\theta = \cos \theta \implies \theta = \pi/4\) because \(\theta\) is an acute angle ?

ganeshie8 (ganeshie8):

Plug that in the length expression for ladder in part a

OpenStudy (mightychondrion):

That was a major brain block. Thank you so much!

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