Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (juan1857):

Solve lnx-ln6=0

jhonyy9 (jhonyy9):

use lna - lnb = ln(a/b)

OpenStudy (juan1857):

so ln(x/6)?

jhonyy9 (jhonyy9):

yes

OpenStudy (juan1857):

is there anymore

jhonyy9 (jhonyy9):

how you know the function logarithmic can being zero

OpenStudy (juan1857):

i don't know

jhonyy9 (jhonyy9):

sorry wait please

jhonyy9 (jhonyy9):

lnx -ln6 =0 lnx =ln6 x=6

OpenStudy (zzr0ck3r):

correct

OpenStudy (juan1857):

oh so that's how you do it

OpenStudy (zzr0ck3r):

well, you sort of skipped something

OpenStudy (zzr0ck3r):

\(\ln(6)-\ln(x)=0\implies \ln(6)=\ln(x) \implies e^{\ln(x)}=e^{\ln(x)}\implies x=6\)

OpenStudy (zzr0ck3r):

but we often skip that step, or argue that since \(\ln(x)\) is a 1-1 function, \(\ln(a)=\ln(b)\implies a=b\)

OpenStudy (zzr0ck3r):

but you could not do that with other functions like \(f(x) = x^2\) because it is true that \(f(2)=2^2=(-2)^2=f(-2)\) but \(2\ne -2\)

OpenStudy (zzr0ck3r):

Oh woops, I thought you asked this question @jhonyy9 . Do you understand @juan1857 ?

OpenStudy (juan1857):

yeah sorta

jhonyy9 (jhonyy9):

ok. @zzr0ck3r ty

OpenStudy (juan1857):

so is it practically what @jhonyy9 only more complicated for me lol

jhonyy9 (jhonyy9):

yes you see it right juan

OpenStudy (zzr0ck3r):

as long as you get it. I just added one more step that often gets skipped and most teachers dont mind. I don't...

OpenStudy (juan1857):

wait, on your example what happened to the lns,

OpenStudy (juan1857):

ok @zzr0ck3r

OpenStudy (juan1857):

thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!