Find the inverse of f(x) = 3x^2. Is the inverse a function? @hero
Is this function one-to-one? Does it pass the horizontal line test?
i.e. is it possible to draw a horizontal line anywhere on the graph that intersects the graph of f(x) in more than one spot?
Follow @zzr0ck3r 's wisdom
yes @zzr0ck3r
@Hero
@18jonea how explain how you conducted your horizontal line test.
this is the graph i got
@Hero
And what happens if you do a HORIZONTAL line test?
oh wait you cant do it any where
You CAN do a horizontal line test. The question is whether it PASSES the horizontal line test.
so yes it does
but what is the inverse
Explain how it passes.
what do you mean
When you say "yes it does" what do you mean by that?
it passes through at 2 points
So if the horizontal line passes through two points, does it mean that the function passes the horizontal line test?
yes
Explain.
i dont know what to explain
What is the purpose of the horizontal line test?
A test use to determine if a function is one-to-one. If a horizontal line intersects a function's graph more than once, then the function is not one-to-one. Note: The function y = f(x) is a function if it passes the vertical line test.
What does "one-to-one" mean?
Oh, look what it says about "horizontal line".
not one to one
Here's more clarification: "one-to-one" means that for a given function, it passes the vertical line test because the vertical line passes through the function exactly "ONCE" and it also passes the horizontal line test, because the horizontal line also passes through the function exactly "ONCE".
In other words, if a function is "one-to-one" it implies that the inverse of the function is also a function.
The biggest advantage to using the horizontal line test is, you can quickly figure out if the inverse of a function is a function.
Which, in this case, we see that the inverse is not a function.
face palm.
If I say, the inverse is NOT a function. It means "NO"
wai tsorry
this one
I'm done.
what @hero
if you can draw a line that passes more than one spot (as you can) then the function does NOT have an inverse.
horizontal
if no such line can be drawn (not the case for you) then the function as an inverse and you need to set it equal to y and solve for x (again, not the case this time).
has an inverse*
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