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Write the expression as a single natural logarithm. 3ln3+3lnc
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\[\log(a)+\log(b)=\log(ab)\]So we have \(3\ln(3)+3\ln(c)=3[\ln(3)+\ln(c)]=\boxed{3\ln(3c)}\)
for some reason MathWay Calculator says ln(27c^3)
yes this is bc. 3ln(3c) = ln(3c)^3 = ln(3^3 *c^3) = ln(27c^3) hope this is really clearly understandably now
ok. ?
let me try to process this
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oh ok so which one is the true answer?
every two bc. 3ln(3c) = ln(27c^3)
ok. Thank You
but this is the end ln(27c^3) bc. this not can simplifie it again like the 3ln3c ok. ?
ok
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